How it is calculated
- pH = −log₁₀[H⁺], and [H⁺] = 10^(−pH)
- pOH = 14 − pH
- [OH⁻] = 10^(−pOH)
- At 25 °C, [H⁺] × [OH⁻] = 1 × 10⁻¹⁴
For logarithms in general, use the logarithm calculator. To write small numbers, use the scientific notation calculator.
Worked example
A solution with pH 3:
- [H⁺] = 1 × 10⁻³ mol/L
- pOH = 14 − 3 = 11, so [OH⁻] = 1 × 10⁻¹¹ mol/L
- It is acidic
A [H⁺] of 0.001 mol/L gives −log₁₀(0.001) = 3.
Why your number may differ
This uses the 25 °C relationship and treats concentration as activity, which is a fair approximation for dilute solutions. Very strong or very concentrated solutions can behave differently.